This page explores the oxidation states (oxidation numbers) shown by the Group 4 elements - carbon (C), silicon (Si), germanium (Ge), tin (Sn) and lead (Pb). The oxidation state of N 2 is 0. Pb +4 O -2 2 + H +1 I -1 → Pb +2 I … Reduction: Pb 4+ (s) + 2e--> Pb 2+ (aq) The lead here starts as Pb 4+ as it combines with 2 O 2-. Cross then superscript S^2 down in front of lead and there ya go. 2) Pb 2+ 3) C in CH 4. Electron Configuration and Oxidation States of Lead. Determine the oxidation state for each of the following. (i) Write a half-equation for the formation of Pb2+ and water from PbO2 in … (ii) Group 14 elements show + 2 and + 4 oxidation states. The oxidation state of an atom is the charge of this atom after ionic approximation of its heteronuclear bonds. The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation (loss of electrons) of an atom in a chemical compound.Conceptually, the oxidation state, which may be positive, negative or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. It looks at the increasing tendency of the elements to form compounds in which their oxidation states are +2, particularly with reference to … Possible oxidation states are +2,4. Just to correct you on this : lead does have an oxidation state of 4+ and elements above such as carbon and tin also have 2+ as an oxidation state. 2) Pb 2+ ion → O.S. The stability of + 2 oxidation state increases and the stability of + 4 oxidation state decreases due to inert pair effect. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). Q. Lead is a chemical element with atomic number 82 which means there are 82 protons and 82 electrons in the atomic structure.The chemical symbol for Lead is Pb. Just look at the electron configuration : the outer $\ce{s^2 p^2}$ orbitals will be able to lose 2 or even 4 electrons, or even gain 4 electrons. +2 for Pb -2 for S. lead(II) sulfide Sulfur has an oxidation number of 2. ) Lead(IV) oxide, PbO2, reacts with concentrated hydrochloric acid to produce chlorine, lead(II) ions, Pb2+, and water. Electron configuration of Lead is [Hg] 6p2. Oxidation under alkaline conditions is easier to effect and is favoured by the formation of the soluble species of lead in the +2 oxidation state. 1) N 2. 5) Ag in Ag 2 O. Within polyatomic ions, you can frequently have oxidation states that are not "normal". Electron Configuration. So, SO42- can be dealt with on its own. Determining oxidation numbers from the Lewis structure (Figure 1a) is even easier than deducing it … = 2+ The oxidation state of Pb 2+ is 2+ 83% (148 ratings) Problem Details. B and Al show + 3 oxidation state, G a and I n show + 1 and + 3 oxidation states and T l mainly shows + 1 oxidation state. THat leaves, though, the oxidation state of Pb to be +2. Within the sulfate ion, each oxygen does have a -2 oxidation state. Since the ion has a -2 charge, the oxidation state of sulfur must be +6. The oxidation number is synonymous with the oxidation state. 4) Fe in Fe 2 O 3. All Chemistry Practice Problems Calculate Oxidation Number Practice Problems. Lead oxide (PbO 2 , with lead as the Pb 4+ ion) is among the stronger oxidizing agents in acidic solution, but it is comparatively weak in alkaline solution. Oxidation: Pb(s) -> Pb 2+ (aq) + 2e- The lead gives away two electrons through the wire and becomes Pb 2+ which combines with SO 4 2-to become lead(II)sulfate. 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